Guzzle is a PHP HTTP Client for sending HTTP requests to APIs . But sending multiple files with a single request sometimes bring on a lot of complexity and people get confused in sending arrays of data within an array for a multipart form, quite confusing.
This snippet will explain how to send multiple files or images with a single request through Guzzle HTTP client with ease. So let's dive straight in the code.
$output = []; foreach ( $images['image'] as $key => $value ) < if ( ! is_array( $value ) ) < $output[] = [ 'name' =>'image[]', 'contents' => fopen( $value->getPathname(), 'r' ), 'filename' => $value->getClientOriginalName() ]; continue; > > $output [] = [ 'name' => 'field_name', 'contents' => \request()->get( 'field_name' ) ]; $output [] = [ 'name' => 'field_name_2', 'contents' => \request()->get( 'field_name_2' ) ]; $output [] = [ 'name' => 'field_name_3', 'contents' => \request()->get( 'field_name_3' ) ];
$client = new Client( [ 'base_uri' => "http://api_url.dev/", ] );
$response = $client->request( 'POST', 'api/endpoint', [ 'headers' => [ 'Authorization' => $token ], 'multipart' => $output ] ); $data = \GuzzleHttp\json_decode( $response->getBody() );
Try it out and let us know in the comment section if you faced any issue. Cheers!
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A web enthusiastic, self-motivated & detail-oriented professional Full-Stack Web Developer from Karachi, Pakistan with experience in developing applications using JavaScript, WordPress & Laravel specifically. Loves to write on different web technologies with an equally useful skill to make some sense out of it.
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